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Local News and Information for Seattle, Washington and surrounding areas KING5com is the official website for KINGTV, your trusted source for breaking news, weather and sports in. A M F Ȃ t Y T r X ̃I C T f B ́A q Y } C V I B N Z Ȃ A ӂ A f ނ h ̃I C T f B B ЂƂ ЂƂ ̑f ނ ǂ 炻 ̂܂ܐH ׂāA A g q Y ܂ 킵 h ̃I C T f B ł B K x Ɏ ̂̂ q Y ̃} C V ANONGMO i ` q g ݊ j ؎ ԍ ƁA c ̓V A Y L @ _ 򃍁 G ŃI C Ђ ɁB f ނ 悢 ̂ł Ȃ A ̂܂܂ł ɔ オ 肽 ܂ B. C op q r s t uv w w v x y.

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Where Tp(h;t;x) = f(t;x) Xp j=2 hj 1f j(t;x) x(t h) x(t) hTp(h;t;x(t) = O(hp1) Theorem The method (h;t;x) is accurate of order p if and only if. @ @ f B N X ~ h ͎ ɍq @ ^ ɓ Ă ܂ A 3 C R q ̃h g X9 @ 𓋍ڂ Ă A1947 N1 ɂ̓C h V i ɓW J A ւ̍U A x { ܂ B 23 A f B N X ~ h ̓t X ɋA ҂ ܂ A ꂪ t X C R ̐ ㏉ ߂Ă̋ ƂȂ ܂ B. 8 z R J U 0 1 2 3 4 Ý.

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P X V V N A x _ Ƃ 鐢 E I ɗL ȁ } R X c ɓ c 邽 ߁A X W E o j ͖ Ɗ Ƀ{ X g Ă B ̃I f B V ŃJ X } U t t } _ E u ̖ڂɗ ܂ A ɏd v ȉ ڂ̃Z ^ ɔ F B Ȓ A } _ E u X ̃ b X 𑱂 ޏ ̂܂ ŕs ȏo p A _ T X Ǝ H 𐋂 c B. Since f is integrable we know R b a f = b a f = supfL(f;P)g supfL(g;P)g= R b a = R b a g #5 Suppose that fis integrable on a;b and that there exists k>0 such that f(x) kfor all x2a;b Prove that 1 f is integrable on a;b Consider the function 1 f Rewrite this as a composite function g= 1. Jan 03, 17chkdsk volume /f /v /r /x /i /c If used without parameters, CHKDSK displays only the volume's status and does not fix any errors If used with the /f, /r, /x.

Consider F and C below F(x, y) = y2 1 x2 i 2yarctan(x)j C r(t) = t2i 5t j, 0 = t = 1 (a) Find a function f such that F = f (b) Use part (a) to evaluate ?C f . / , = >. A B y t p ¬.

Final Velocity (t) v f = v i at m/s Final Velocity (d) v f 2 = v i 2 2ad m/s Speed (circular) v = 2pr/T m/s Angular Speed ω = Δθ/Δt rad/s Angular Accel α = Δω/Δt rad/s 2 Acceleration a = Dv/Dt m/s 2 Acceleration (cent) a c = v 2 /r m/s 2 Acceleration (gravity) g = F/m m/s 2 Force F = ma N or kgm/s 2 Weight F. O d l s s ^ ~ ̃G X e B G W ł́A ɍ 킹 t F C X C L O g g g Ă ܂ B \ ́A ܂ ͗ Ɋm F ̂ d b A œ ̊m Ă ܂ B z y W ̂ \ ͊m ł͂ ܂ ̂ŁA l ̎肩 ` 銴 t F C V f B. The expression ↦ (,) (read the map taking x to f(x, t 0)) represents this new function with just one argument, whereas the expression f(x 0, t 0) refers to the value of the function f at the point (x 0, t 0) Index notation Index notation is often used instead of functional notation.

17 N x @ 32 R v t f B X e j X g i g o Z b e j X y l A O ؎R e j X R g l ɂ́A ς b ɂȂ肠 肪 Ƃ ܂ B. K f ̖؁X A Ȃǂ̐ A q l ̃K f ̂ k Ȃǂ ܂ B o b X A z e ⃌ X g ̐ ݁A E F f B O f B X v. De ne f X!R by f(x) = d(T(x);x) The function f is continuous, since if x n!xand y n = T(x n), then y n!T(x) by the continuity of T, and f(x n) = d(y n;x n) !d(T(x);x) = f(x) by the continuity of d Since f X!R is a continuous function on a compact set, it attains its minimum value at some a2X If T(a) 6=a, then f(T(a)) = d(T(T(a));T(a)) <d(T.

Ђ̃p \ R g ѓd b ł ł ǂ ł l b g m F ł 閳 T r X uUbiqMail v p ̏ꍇ A u M v ɂ̓E B X ` F b N s ܂ iUbiqMail 瑗 M 郁 ̓E B X ` F b N ΏۊO ł j B. Vision Quest Tokyo Xray 鍡 N ő ̖ O t F X e B o wVision Quest The Gathering @02 x ̑S L ^ BDVD ɂ́uThe Gathering 02 v ̃h L ^ f A M d ȃg X A e B X g ̃ C u p t H } X łȂ A T C P f b N A j V A A e B X g A I K i C U A _ T ̃N C W ȕ 䗠 f ܂ł ԗ BCD ɂ Skazi ̃L g b N wI'm Stuck x ͂ ߁AInfected Mushroom wEvadawn x. 2 3 4 $ 5 6 3 7 *1 $ 8 9 ) ) 3 ;.

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Taylor Method assume f 2Cp, so x 2Cp1(a;b) Set f1(t;x) = f(t;x), and recursively define fj1(t;x) = Dtfj(t;x)Dxfj(t;x)f(t;x) so that Dtx(t) = f(t;x(t)) )D j tx(t) = fj(t;x(t)) Taylor Method of order p set = Tp;. Sep 19, Stack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange. R f(x)dx = F(x) means F0(x) = f(x) We use the notation R f(x)dx to denote an antiderivative for f(x) and it is called an indefinite integral A definite integral has the form Z b a f(x)dx = Z f(x)dx b a = F(b)−F.

MATH 140B HW 1 SOLUTIONS Problem1(WR Ch 5 #6) Suppose (a) f is continuous for x ‚0, (b) f 0(x) exists for x ¨0, (c) f (0) ˘0, (d) f 0 is monotonically increasing, Put g(x) ˘ f (x) x (x ¨0)and prove that g is monotonically increasing Solution If we can prove that g0(x) ¨0 for x ¨0, then this will show that g is monotonically increasing (by Theorem 511a) By the quotient rule,. Y Ő ܂ꂽ 䂪 q ́A g ̓ ΐS( C) A S ΐg ̓ ŏ Q Ȃ ` W _ ȗ q Ɉ Ă ܂ B ߔN A x r } b T W u ɂȂ Љ Ŏ グ l ɂȂ ė ܂ ϊ v Ă ܂ B ̎q Čo ⌤ 瓾 X ̋Z @ e ̓` w ` Ȃ L Ȑe q ֌W z Ă F Ă ܂ B ڂ ͑ \ A. I L Ђ̌ T C g ł B Ə AIR A i E T r X Ȃǂ f ڂ Ă ܂ B E t @ j b g ̐U ɂ́A I L Ǝ ́u m v X R v ̗p B v X s Ȃ ƂœK x Ȍ ݂ u y ʁv u v u X ̑傫 v Ƃ U ɕK v 3 v f Ńo X 邱 Ƃ ł ܂ B \ ʂɕ U } R Q V z m v X R ́A a140 ~ ̑ ^ t F C g } O l b g p ͂Ȏ C H ƁA50 ~ ̑ a { C X R C ɂ h C u A m ȃs X g V Ă ܂ B ܂ A U ւ A ~ _ C L X g t ́A U ɂ m ɔ p 󂯎~ ߁A t щ.

L b Y N X i14 Έȉ j A r M i i2 N j A i35 Έȉ j A V j A i36 Έȏ j A W F h i50 Έȏ j E A O { h i9 t B g ȏ j A { f B { h. The given condition implies that F(x) = F(b)−F(x) Therefore, F′(x) = 0 which implies that f(x) = 0 14 Define h(x) = f(b) ∫x a g(x)dxf(a) ∫b x g(x)dxforall x ∈ a,b Nowh(a) = f(a) ∫b a g(x)dx ≤ ∫b a f(x)g(x)dx ≤ f(b) ∫b a g(x)dx = h(b) Apply the IVP 15 Let f a,b → R be continuous Define F(x) = ∫x a f(t. F f B E N g E A h @ @ x e B E t @ E f E { X R iS) AC AUDIOPHILE @APL.

T C O f B X N E A e B b g E h b a r ̊e p i ̔ E ʔ́B f B X N A j z A X p C N ADVD Ȃǂ̊e p i ̔ E ʔ̂ s Ă ܂ B US I v ̓ { łƂ ŁA { ̃g b v ` ꓯ ɉ A x őΐ s Ƃɂ A E ɒʗp { ` Ă邱 Ƃ ړI Ƃ A J Â. The problem is roughly speaking the following If f U → R m is a differentiable function (where U ⊂ R n is open) and if x th, x, h ∈ R n, t ∈ 0, 1 is the line segment in question (lying inside U), then one can apply the above parametrization procedure to each of the component functions f i (i = 1, , m) of f (in the above. S 24 j A Ǝ哱 ^ ۈ玖 Ɓi Ǝ哱 ^ ۈ玖 Ə v ́A Ǝ哱 ^ ۈ玖 Ɣ ⏕ { v j j A .

B = z ¨. F(x)dx This value is f(b)−f(a) (d) Z b a f(x)dt This is a little tricky since the integral is in terms of t, but f is an expression in x, it will be constant with respect to t The answer f(x)(b−a) 3 Evaluate, where possible If not, state why (a) Z 4 1 x2 −x1. T v ÁF ʎВc @ l m t C O f B X N ÁF ЃN u W j A ǁF S r ` f B X N t F X e B o s ψ F N7 18 ( y) @1300 @ ` @7 19 ( ).

Define f € (R)* by f(1, y, z) = 2x y and T R$ R by T(x, y, z) = (3x 2y, 1, 1z) (a) Compute t'f) (b) Compute the matrix associated to T' with resepect to the dual basis of the standard basis of R3 (c) Compute the matrix associated to T with respect to the standard basis of R3. X R x R s ̔ e @ E e E w A T A f B X ~ E m x V i10miL renovation j J b g X ^ C O ͂ u V v v u10miL X p v A ̃_ W } 郁 j l C B10miL ňꏏ ɃL C Ȕ n ߂܂ 񂩁H w10miL Web x ւ悤 I w10miL Web x ́A 10 N11 ɕx R s OPEN w A T w10miL renovation x HP ł B. HTX77HDX ́A3D f ` ƃI f B I ^ ` l iARC j ɑΉ Ő ̃C ^ t F X uHDMI ver14a v 𓋍ڂ Ă ܂ B ʂ̑ 3D f ` 邽 ߂̍ŐV K i ł A I L ́A3D e r 3D u C f B X N v W Ă āA f Ɖ ̏㎿ 3D V A ^ y ߂ d l ̗p Ă ܂ BHTX77HDX ́A3 HDMI ͒ q 𑕔 Ă ܂ ̂ŁA ݂ 珫 ɂ킽 Ă ܂ ܂ȋ@ ڑ ł 郍 O C t d l ƂȂ Ă ܂ B.

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Wrt K x isminimumelementof S iffforall λ K ∗ 0, x istheuniqueminimizer of λ T z over S x S minimal element wrt K • if x minimizes λ T z over S forsome λ K ∗ 0,then x isminimal S x 1 x 2 λ 1 λ 2 • if x isaminimalelementofa convex set S,thenthereexistsanonzero λ K ∗ 0 suchthat x minimizes λ T z over S Convexsets 2–22. Dr along the given curve C. R { M u V p c W M s R h p I Ձt AVCL 10 N6 2 iavexCLASSICS j SACD n C u b h E f B X N 艿3,000 ~ i ō j.

T r X u Ǝ哱 ^ ۈ玖 Ɓv i t { j t { 哱 ̐V Ȏq ǂ q Ďx Ƃł B Ǝ哱 ^ ̎ Ə ۈ玖 Ƃ 厲 Ƃ āA l ȏA J ` ԂɑΉ ۈ T r X ̊g s A d Ǝq ĂƂ̗ Ɏ 邱 Ƃ ړI Ƃ Ă ܂ B ^ c { ݐ ɂ ẮA q ǂ E q Ďx V x ̏ K ͕ۈ玖 Ɠ ̌ 艿 i ɏ x s ܂ B Ȃ @ i22 N @ 164 j y тȂ q ǂ i N . Graph f(x)=b^x Find where the expression is undefined The domain of the expression is all real numbers except where the expression is undefined In this case, there is no real number that makes the expression undefined The vertical asymptotes occur at areas of infinite discontinuity. 0 1 2 3 4 $ # 5 n C t o §.