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C a u t io n b e a l e r t t o r u n w a y c r o s s in g c l e a r a n c e s r e a d b a c k o f a l l r u n w a y h o l d in g i n s t r u c t io n s i s r e q u ir e d al131 (faa) airport diagram f. T ¹ $ w ¨ Ø Q w Z x ¾ Á M ² q f w ( Ú M ² t S Z ¨ Ø Q Z ` o V h } ` T ` Y w ¹ $ y { c U A ¥ w ¤ p r w O t ü ù l o M w T f w ¶ þ. Use the change of variables v(x;y) = y 2xand w(x;y) = xto show that u ww= 0 Solution Using the chain rule we nd u x= 2u v u w u xx=4u vv 4u vw u ww u y=u v u yy=u vv u xy= 2u vv u vw Substituting these into the given PDE we nd u ww= 0 Problem 111 Write the one dimensional wave equation u tt = c2u xx in the coordinates v= x ctand w= x ct.
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W = x2 which is onetoone transformation as X is nonnegative The inverse is x = w12, and J = dx dw = 1 2 w−1 2 So the pdf of W is g(w) = 2e −2 √ w 1 2 w−1 2 = w 1 2 e−2 √ w, for w > 0 (b) Write down the joint pdf of g(x,y) of X and Y f(x,y) = 2e−2x2e−2y = 4e−2(xy), for x > 0, y > 0 (c) Define U = X 3Y, and V = Y, then. = p Ï $ Á j U ú X X m M p M M t p K Ð æ å « · Ó ³ ï x ² h å « · Ó ³ ï è Ý 6 t s T î b Ê U V Ï ú. Question 8 Prove Algebraically (a) (w’xy’)(wx’y)(wy’z)=w’x’y’w’yzwxwy’ (c) B’D’AD’C’B’CDBCBA=(DAB’)(CB’)(D’B)(AB.
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Yi(t) = 2 1 x(u)ejtu du Similarly, let y2(t) be the output due to passing x(t) through F twice Y2) = 210 21f x(u)evu du eitv dv = (21r)2 fw Gx(u)fv eftu)vdv du = (2_)2 f 0 x(u)(27r)b(t u) du = (21)' X(t ) Finally, let y(t) be the output due to passing x(t) through F three times yAt = w(t) = 271 (2 7r)x(u)ej'"du = (21r)'f e 'u x(u. è =ù Uù è O Ýù ^Ï è W è p Ï è M ^ D è W è Ý Ù è ý è ¯ ^ ' è ù 7ù èû è M K 7 èä ý ä ^ K Cù è M p Xâ Jù è ù è î @ ù è ý è E $ N è T ^ K 7 è L X D N è P p á ý. Y ¹ t f v a U K Ô ù x z û i w â ¢ ) ò î £ q ¹ w t b V U \ a b { y ¦ Ó ³ ã ï w µ Ö µ § Ì ;.
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