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C) T R3 → R defined by T(a 1,a 2,a 3) = 2a 1 a 2 −3a 3 Solution b) T(1,0,0) = (2,1) T(0,1,0) = (3,0) T(0,0,1) = (−1,1) and therefore Tγ β = 2 3 −1 1 0 1 c) T(1,0,0) = 2 T(0,1,0) = 1 T(0,0,1) = −3 and therefore Tγ β = 2 1 −3 Exercise 2214 let V = P(R), and for j ≥ 1 define T j(f(x)) = f(j)(x), where f(j)(x) is. (Последнее обновление ноябрь 19) H e Z k b f _ g _ g b y h e Z k b _ B g n h j f Z p b y, h l h j m x u h b j Z _ f. I F 9900 ~ i ō j \ F ɂ f B Y j v Z X Ɩ b v Z X R X ` ߑ f b N X l p Ɩ b x y f B Y j v Z X, x , Ɩ b, ߑ , R X ` z y ` R g M U X J g 2 d ɏd Ȃ A s N ̃ Y ̏ 肪 C G ƃS h ̃h X B w b h s X A C ͊܂܂ ܂ B (c)Disney costume C Z X i ł B { i ̓f B Y j v Z X i P A V f A I P A A G A W X ~ A x j ̑ D ȕ ̃R N V Ƃ āA n E B ̃R X ` Ƃ āA X e W ̈ߑ Ƃ āA s A m.
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I f B Y j V U @ A f B Y j O b Y A f B Y j v Z X i F 1,487 @ @ \ F ʏ 24 Ԉȓ ɔ ̃V \ 邾 ŁAi Pod J X ^ ł ̂ B. ~ b L f B Y j L N ^ ̎G ݂Ȃ AOI f p g ŁB f B Y j L N ^ O b Y ̒ʔ́B. In this *improvised* video, I show that if is a function such that f(xy) = f(x)f(y) and f'(0) exists, then f must either be e^(cx) or the zero function It'.
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