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If x ∈ B, then y ∈ f(B), which contradicts the previous statement, so we must have x /∈ B This implies x ∈ A \ B, and hence y ∈ f(A\B) 1222 (c) Prove that f−1(f(A)) = A for all A ⊆ X iff f is injective Proof =⇒ Let x 1,x 2 ∈ X with f(x 1) = f(x 2) Let A = {x 1} Then f(A) = {f(x 1)}, and since f(x. ß³g ² ã , &Ì ã Ø } x, aÄ x ã } x, ÅÀ } x, 5 _ Ù , a 9 Ù, , Ç ã Ø, ö Ø ã ß³G ã ² ?, Ù J ?, a Ë ?(. Â Ë ­ { Ã !.

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